# Line slope calculator x+3y=8

**Straight line given by points A[2; 2] and B[5; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.3333x+2.6667

**Canonical form of the line equation:**x+3y-8 = 0

**Parametric form of the line equation:**

x = 3t+2

y = -t+2 ; t ∈ R

**Slope:**m = -0.3333

**Slope angle of line: φ =**-18°26'6″ = -0.3218 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 2.6667

**Distance line from the origin:**d

_{0}= 2.5298

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; -1)

**Normal vector: n =**(1; 3)

**Midpoint of the segment AB: M =**[3.5; 1.5]

**Perpendicular Bisector equation:**3x-y-9 = 0

**Vector OA = (2; 2) ; |OA| = 2.8284**

**Vector OB = (5; 1) ; |OB| = 5.099**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**