# Line slope calculator 4x+7y=47

**Straight line given by points A[3; 5] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.5714x+6.7143

**Canonical form of the line equation:**4x+7y-47 = 0

**Parametric form of the line equation:**

x = 7t+3

y = -4t+5 ; t ∈ R

**Slope:**m = -0.5714

**Slope angle of line: φ =**-29°44'42″ = -0.5191 rad

**X intercept:**x

_{0}= 11.75

**Y intercept:**y

_{0}= q = 6.7143

**Distance line from the origin:**d

_{0}= 5.8296

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(7; -4)

**Normal vector: n =**(4; 7)

**Midpoint of the segment AB: M =**[6.5; 3]

**Perpendicular Bisector equation:**7x-4y-33.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 35**

**Angle ∠ AOB = 53°19'32″ = 0.9307 rad**